{VERSION 6 0 "IBM INTEL NT" "6.0" } {USTYLETAB {CSTYLE "Maple Input" -1 0 "Courier" 0 1 255 0 0 1 0 1 0 0 1 0 0 0 0 1 }{CSTYLE "2D Math" -1 2 "Times" 0 1 0 0 0 0 0 0 2 0 0 0 0 0 0 1 }{CSTYLE "2D Comment" 2 18 "" 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 1 } {CSTYLE "" -1 256 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 }{CSTYLE "" -1 257 "" 0 1 0 0 0 0 0 1 0 0 0 0 0 0 0 0 }{PSTYLE "Normal" -1 0 1 {CSTYLE "" -1 -1 "Times" 1 12 0 0 0 1 2 2 2 2 2 2 1 1 1 1 }1 1 0 0 0 0 1 0 1 0 2 2 0 1 }{PSTYLE "Heading 1" -1 3 1 {CSTYLE "" -1 -1 "Times " 1 18 0 0 0 1 2 1 2 2 2 2 1 1 1 1 }1 1 0 0 8 4 1 0 1 0 2 2 0 1 }} {SECT 0 {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 36 "restart;\nwith(plots ):\nwith(DEtools):" }}}{SECT 1 {PARA 3 "" 0 "" {TEXT -1 65 "Example 1: An Electric Circuit with constant voltage (DC voltage)" }}{EXCHG {PARA 0 "" 0 "" {TEXT -1 19 "Clear the variable " }{XPPEDIT 18 0 "y;" "6#%\"yG" }{TEXT -1 45 ", which currently is defined as a function.\n \+ " }{MPLTEXT 1 0 7 "y:='y':" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 47 "A d ifferential equation for an electric circuit" }{MPLTEXT 1 0 32 "\nDE2: =12*y(x)+4*diff(y(x),x)=60;" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 48 "A \+ particular solution plotted on the slope field" }{MPLTEXT 1 0 171 "\ni nitialCondition:=[[0,0]];\nDEplot(DE2, y(x), x=-1..7,initialCondition, y=-1..7,linecolor=blue,title=\"Particular solution to an electric circ uit diff. eq. through (0,0)\");\n" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 51 "Several particular solutions plotted simultaneously" }{MPLTEXT 1 0 167 "\nmoreInitConds:=[[0,0],[0,5],[0,7]];\nDEplot(DE2, y(x), x=-1.. 7,moreInitConds,y=-1..7,linecolor=[blue,red,maroon],title=\"Several pa rticular solutions to y'(x)=15-3*y\");" }}}{EXCHG {PARA 0 "" 0 "" {TEXT 256 16 "General solution" }{TEXT -1 46 " to the electric circuit differential equation" }{MPLTEXT 1 0 19 "\ndsolve(DE2, y(x));" }}} {EXCHG {PARA 0 "" 0 "" {TEXT -1 50 "Clear the value of C1, which was p reviously used.\n" }{MPLTEXT 1 0 9 "C1:='C1':" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 56 "subs(\{y(x)=0,x=0\},y(x)=5+exp(-3*x)*C1);\nC1:=s olve(%,C1);" }}}{EXCHG {PARA 0 "" 0 "" {TEXT 257 19 "Particular soluti on" }{TEXT -1 28 " for initial condition (0,0)" }{MPLTEXT 1 0 107 "\ny :=x->5+exp(-3*x)*C1;\nplot(y(x),x=-1..7,y=-1..7,title=\"Particular sol ution to y'(x)=15-3y through (0,0)\");" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}}}{SECT 1 {PARA 3 "" 0 "" {TEXT -1 68 "Example 2: An Electric Circuit with oscil lating voltage (AC voltage)" }}{EXCHG {PARA 0 "" 0 "" {TEXT -1 19 "Cle ar the variable " }{XPPEDIT 18 0 "y;" "6#%\"yG" }{TEXT -1 43 ", which \+ currently is defined as a function." }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 36 "restart;\nwith(plots):\nwith(DEtools):" }}}{EXCHG {PARA 0 "" 0 "" {TEXT -1 47 "A differential equation for an electric circuit" } {MPLTEXT 1 0 69 "\ny:='y': #Clear value of y\nDE3:=12*y(x)+4*diff(y(x ),x)=60*sin(60*x);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 26 "dsolv e(\{DE3,y(0)=0\},y(x));" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 30 " assign(%);\ny:=unapply(y(x),x);" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 127 "plot1:=plot(y(x),x=0..1,y=-1..1,color=red,legend=\"Current\") :\ndisplay(plot1,title=\"Circuit under alternating voltage (~9.5Hz)\") ;" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 147 "plot2:=plot(sin(60*x) /3,x=0..1,y=-1..1,color=blue,legend=\"Voltage / 180\"):\ndisplay([plot 1,plot2],title=\"Current and voltage/180 plotted together\");" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 5 "y(x);" }}}{EXCHG {PARA 0 "> \+ " 0 "" {MPLTEXT 1 0 0 "" }}}}}{MARK "2" 0 }{VIEWOPTS 1 1 0 1 1 1803 1 1 1 1 }{PAGENUMBERS 0 1 2 33 1 1 }