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1 2 2 1 2 2 2 0 0 0 1 } {CSTYLE "" -1 273 "Times" 1 12 0 0 0 1 2 2 1 2 2 2 0 0 0 1 }{CSTYLE "" -1 274 "Times" 1 12 0 0 0 1 2 2 1 2 2 2 0 0 0 1 }} {SECT 0 {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 0 "" }}{PARA 208 "" 0 "" {TEXT 203 0 "" }{TEXT 206 0 "" }{TEXT 203 8 "MATH 151" }}{PARA 209 "" 0 "" {TEXT 275 0 "" }{TEXT 203 29 "LABORATORY ASSIGNMENT Bonus 1" }} {PARA 201 "" 0 "" {TEXT 207 2 " " }{TEXT 275 0 "" }{TEXT 208 24 "IMPL ICIT DIFFERENTIATION" }}{PARA 201 "" 0 "" {TEXT 275 0 "" }}{PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 2 " " }}{PARA 0 "" 0 "" {TEXT 276 16 " The function " }{TEXT 209 1 "f" }{TEXT 276 3 " ( " }{TEXT 210 1 "x" }{TEXT 211 3 " ) " }{TEXT 276 13 "is said to be" } {TEXT 212 19 " implicitly defined" }{TEXT 276 96 " by the equation \+ \+ " }}{PARA 0 "" 0 "" {TEXT 276 196 " \+ \+ \+ " }{MPLTEXT 1 0 0 "" }{TEXT 276 70 " \+ (*) E( " } {TEXT 213 1 "x" }{TEXT 276 3 " , " }{TEXT 214 1 "y" }{TEXT 276 7 " ) = 0" }}{PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 20 " provided that E( " }{TEXT 215 1 "x" }{TEXT 276 3 " , " }{TEXT 216 3 " f " }{TEXT 276 2 "( " }{TEXT 217 1 "x" }{TEXT 276 22 " ) ) = 0 \+ for all " }{TEXT 218 2 "x " }{TEXT 276 17 "in some interval " }{TEXT 219 2 "I " }{TEXT 276 1 "." }}{PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 32 " For example, if E( x , y ) = " }{XPPEDIT 18 0 "x^2+y^2-4;" "6#,(*$)%\"xG\"\"#\"\"\"F(*$)%\"yGF'F(F(\"\"%!\"\"" } {TEXT 276 9 ", then " }{XPPEDIT 18 0 "f[1](x) = sqrt(4-x^2);" "6#/-& %\"fG6#\"\"\"6#%\"xG-%%sqrtG6#,&\"\"%F(*$)F*\"\"#F(!\"\"" }{TEXT 276 6 " and " }{XPPEDIT 18 0 "f[2](x) = -sqrt(4-x^2);" "6#/-&%\"fG6#\"\"# 6#%\"xG,$-%%sqrtG6#,&\"\"%\"\"\"*$)F*F(F1!\"\"F4" }{TEXT 276 98 " both satisfy the equation E( x , y ) = 0, and thus both are implicitly de fined by this equation." }}{PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 183 " It is, however, frequently difficult or impossi ble to solve an equation of the form E(x,y) = 0 for y in terms of x; \+ this is the case in the example and exercises below. (Try it!) " } {TEXT 220 0 "" }{TEXT 276 0 "" }{TEXT 221 0 "" }{TEXT 276 81 "Neverthe less, such an equation may implicitly define one or more functions of \+ x. " }}{PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 183 " It is possible to find the derivative of an implicitly defined func tion at a given point without first solving the equation (*) for y i n terms of x by using a technique called " }{TEXT 222 24 "implicit \+ differentiation" }{TEXT 223 1 "." }{TEXT 276 65 " We differentiate bot h sides of the equation (*) with respect to " }{TEXT 224 2 " x" }{TEXT 276 9 ", viewing" }{TEXT 225 4 " y " }{TEXT 276 19 " as a function o f " }{TEXT 226 1 "x" }{TEXT 276 72 ", applying the usual differentiat ion rules and ultimately solving for " }{TEXT 227 3 "dy " }{TEXT 276 1 "/" }{TEXT 228 3 " dx" }{TEXT 276 78 " in terms of x and y . Thi s procedure can be carried out by using appropriate " }{TEXT 229 5 "Ma ple" }{TEXT 276 10 " commands." }}{PARA 0 "" 0 "" {TEXT 276 0 "" }} {PARA 210 "" 0 "" {TEXT 203 9 " Example" }}{PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 17 " Find the slope," }{TEXT 230 2 " m" }{TEXT 276 42 ", of the tangent line to the graph of the " }{TEXT 231 8 "cardioid" }{TEXT 276 17 " with equation: " }}{PARA 0 "" 0 "" {TEXT 276 70 " \+ " }}{PARA 0 "" 0 "" {TEXT 276 9 " " }{XPPEDIT 18 0 "x^4+y^4-4*(y^3+x^2+x^2*y)+2*x^2*y^2 = 0;" "6#/,**$)%\"xG\"\"%\"\" \"F)*$)%\"yGF(F)F)*&F(F),(*$)F,\"\"$F)F)*$)F'\"\"#F)F)*&F3F)F,F)F)F)! \"\"*(F4F)F2F))F,F4F)F)\"\"!" }{TEXT 276 19 " at the point " } {TEXT 232 1 "P" }{TEXT 276 5 " = " }{TEXT 233 2 "( " }{XPPEDIT 18 0 "(2+sqrt(3))/2;" "6#*&,&\"\"#\"\"\"-%%sqrtG6#\"\"$F&F&F%!\"\"" }{TEXT 276 5 " , " }{XPPEDIT 18 0 "(2*sqrt(3)+3)/2;" "6#*&,&*&\"\"#\"\"\"-% %sqrtG6#\"\"$F'F'F+F'F'F&!\"\"" }{TEXT 276 2 " " }{TEXT 234 1 ")" } {TEXT 276 1 "." }}{PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 48 " First, we enter the equation of the cardioid:" }} {PARA 0 "" 0 "" {TEXT 276 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 8 "restart:" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 42 "eq:=x^4+y^ 4-4*(y^3+x^2+x^2*y)+2*x^2*y^2=0;" }}{PARA 0 "" 0 "" {TEXT 276 0 "" }} {PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 11 "" 1 "" {XPPMATH 20 "/,.*$I \"xG6\"\"\"%\"\"\"*$I\"yGF&F'F(*$F*\"\"$!\"%*$F%\"\"#F-*&F%F/F*F(F-*&F %F/F*F/F/\"\"!" }}}{PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 77 " Next, we sketch a graph of the cardioid in the coordi nate plane using the " }{TEXT 235 6 "Maple " }{TEXT 276 8 "command " } }{PARA 0 "" 0 "" {TEXT 276 1 " " }{TEXT 236 12 "implicitplot" }{TEXT 237 1 " " }{TEXT 276 25 "which is located in the " }{TEXT 238 7 "plot s p" }{TEXT 276 21 "ackage. 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" }}{PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 50 " To differentiat e this equation with respect to " }{TEXT 246 1 "x" }{TEXT 276 13 ", w e use the " }{TEXT 247 5 "diff " }{TEXT 276 8 "command." }}{EXCHG {PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "> " 0 "" {MPLTEXT 1 0 16 "de q:=diff(eq,x);" }}{PARA 11 "" 1 "" {XPPMATH 20 "/,2*$I\"xG6\"\"\"$\"\" %*&-I\"fGF&6#F%F'-I%diffG%*protectedG6$F*F%\"\"\"F(*&F*\"\"#F-F1!#7F%! \")*&F%F1F*F1F5*&F%F3F-F1!\"%*&F%F1F*F3F(*(F%F3F*F1F-F1F(\"\"!" }}} {PARA 0 "" 0 "" {TEXT 276 18 " Here Maple uses " }{XPPEDIT 18 0 "diff (f(x), x);" "6#-%%diffG6$-%\"fG6#%\"xGF)" }{TEXT 276 46 " to denote f \+ '( x ), the derivative of f( x )." }}{PARA 0 "" 0 "" {TEXT 276 20 " W e now solve for " }{XPPEDIT 18 0 "diff(f(x), x);" "6#-%%diffG6$-%\"fG 6#%\"xGF)" }{TEXT 276 2 " :" }}{PARA 0 "" 0 "" {TEXT 276 0 "" }} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 37 "Diff(f(x),x)=solve(deq,diff( f(x),x));" }}{PARA 11 "" 1 "" {XPPMATH 20 "/-I%DiffG6$%*protectedGI(_s yslibG6\"6$-I\"fGF(6#I\"xGF(F-,$*(F-\"\"\",**$F-\"\"#F0!\"#F0F*F4*$F*F 3F0F0,**$F*\"\"$F0F5!\"$F2!\"\"*&F-F3F*F0F0F:F:" }}}{EXCHG {PARA 0 "" 0 "" {TEXT 276 111 " The single Maple command \"implicitdiff\" combine s the above computations but uses \"y\" rather than \"f(x)\"." }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 7 "y:='y';" }}{PARA 11 "" 1 "" {XPPMATH 20 "I\"yG6\"" }}}{EXCHG {PARA 0 "" 0 "" {TEXT 276 53 "(Previo usly,we had replaced y by f(x); the command \"" }{TEXT 248 6 "y:='y'" }{TEXT 276 17 " \"undoes this.) " }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 3 "eq;" }}{PARA 11 "" 1 "" {XPPMATH 20 "/,.*$I\"xG6\"\"\"%\"\"\"* $I\"yGF&F'F(*$F*\"\"$!\"%*$F%\"\"#F-*&F%F/F*F(F-*&F%F/F*F/F/\"\"!" }}} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 27 "dydx:=implicitdiff(eq,y,x);" }}{PARA 11 "" 1 "" {XPPMATH 20 ",$*(I\"xG6\"\"\"\",**$F$\"\"#F&!\"#F& I\"yGF%F**$F+F)F&F&,**$F+\"\"$F&F,!\"$F(!\"\"*&F$F)F+F&F&F1F1" }}} {PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 12 " The p oint " }{TEXT 249 1 "P" }{TEXT 276 18 " has coordinates " }{TEXT 250 1 "x" }{TEXT 276 3 " = " }{XPPEDIT 18 0 "(2+sqrt(3))/2;" "6#*&,&\"\"# \"\"\"-%%sqrtG6#\"\"$F&F&F%!\"\"" }{TEXT 276 8 " and " }{TEXT 251 1 "y" }{TEXT 276 5 " = " }{XPPEDIT 18 0 "(2*sqrt(3)+3)/2;" "6#*&,&*& \"\"#\"\"\"-%%sqrtG6#\"\"$F'F'F+F'F'F&!\"\"" }{TEXT 276 24 " , so in \+ order to find " }{TEXT 252 1 "m" }{TEXT 276 30 ", the slope of the tan gent at " }{TEXT 253 2 "P," }{TEXT 276 17 " we must replace " }{TEXT 254 0 "" }{TEXT 276 10 " y by " }{XPPEDIT 18 0 "(2*sqrt(3)+3)/2;" "6#*&,&*&\"\"#\"\"\"-%%sqrtG6#\"\"$F'F'F+F'F'F&!\"\"" }{TEXT 276 8 " \+ and " }{TEXT 255 1 "x" }{TEXT 276 9 " by " }{XPPEDIT 18 0 "(2+s qrt(3))/2;" "6#*&,&\"\"#\"\"\"-%%sqrtG6#\"\"$F&F&F%!\"\"" }{TEXT 276 28 " in the formula for dy/dx." }}{PARA 0 "" 0 "" {TEXT 276 0 "" }} {EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 45 "subs(y=(2*sqrt(3)+3)/2,x=(2+ sqrt(3))/2,dydx);" }}{PARA 11 "" 1 "" {XPPMATH 20 ",$*(,&\"\"\"F%*$\" \"$#F%\"\"#F(F%,**$F$F)F%!\"&F%F&!\"#*$,&F&F%#F'F)F%F)F%F%,**$F/F'F%F. !\"$F+!\"\"*&F$F)F/F%F%F4F4" }}}{PARA 0 "" 0 "" {TEXT 276 0 "" }} {PARA 0 "" 0 "" {TEXT 276 59 " Simplifying this complicated fraction, we find the slope " }{TEXT 256 1 "m" }{TEXT 276 37 " of the tangent l ine to the graph at " }{TEXT 257 1 "P" }{TEXT 276 7 " to be:" }}{PARA 0 "" 0 "" {TEXT 276 0 "" }}{EXCHG {PARA 0 "" 0 "" {TEXT 276 0 "" }} {PARA 0 "> " 0 "" {MPLTEXT 1 0 15 "m:=simplify(%);" }}{PARA 11 "" 1 "" {XPPMATH 20 "!\"\"" }}}{PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 47 " In order to get a decimal representation for " } {TEXT 258 1 "m" }{TEXT 276 52 " accurate to ten significant digits, we may use the " }{TEXT 259 5 "evalf" }{TEXT 276 10 " command." }} {PARA 11 "" 0 "" {TEXT 277 0 "" }}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 9 "evalf(m);" }}{PARA 11 "" 0 "" {TEXT 277 0 "" }}{PARA 11 "" 1 "" {XPPMATH 20 "$!\"\"\"\"!" }}}{EXCHG {PARA 0 "" 0 "" {TEXT 276 0 "" }} {PARA 0 "" 0 "" {TEXT 276 0 "" }}}{EXCHG {PARA 0 "" 0 "" {TEXT 276 37 " The equation of the tangent is y = " }{TEXT 260 1 "m" }{TEXT 276 5 "(x - " }{XPPEDIT 18 0 "(2+sqrt(3))/2;" "6#*&,&\"\"#\"\"\"-%%sqrtG6#\" \"$F&F&F%!\"\"" }{TEXT 276 5 " ) + " }{XPPEDIT 18 0 "(2*sqrt(3)+3)/2;" "6#*&,&*&\"\"#\"\"\"-%%sqrtG6#\"\"$F'F'F+F'F'F&!\"\"" }{TEXT 276 80 " . We can plot the cardioid and its tangent on the same set of axes a s follows:" }}{PARA 0 "" 0 "" {TEXT 276 0 "" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 63 "A:=implicitplot(eq,x=-4..4,y=-1..4,grid=[100,100], color=black):" }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 61 "B:=plot(m* (x-(2+sqrt(3))/2)+(2*sqrt(3)+3)/2,x=-4..4,y=-1..5):" }}}{EXCHG {PARA 211 "" 0 "" {TEXT 276 0 "" }{TEXT 203 57 "NOTE THAT THE ABOVE COMMANDS END WITH \":\"AND NOT \";\"." }}}{EXCHG {PARA 0 "> " 0 "" {MPLTEXT 1 0 15 "display([A,B]);" }}{PARA 13 "" 1 "" {GLPLOT2D 400 300 300 {PLOTDATA 2 "6&-%+AXESLABELSG6'Q\"x6\"Q\"yF'-%%FONTG6$%*HELVETICAG\"#5 %+HORIZONTALGF.-%'CURVESG6g]m7$7$$!33WXXXXXXD!#<$\"3Nz+'\\bPO,\"F67$$! 3Y<*f,1Voa#F6$\"36???????5F67$F97$$!3-)*pj'QJqa#F6$\"3w`5%fa(=@5F67$7$ $!3yIw*[#4ecDF6$\"3sqqqqqqq5F6F?7$FE7$$!3=LE6D]!zb#F6$\"3MwL\\?')[y5F6 7$7$$!3[=H(HrM`c#F6$\"3L@@@@@@@6F6FK7$7$$!3#*=H(HrM`c#F6FT7$$!3MBGEJ \\PnDF6$\"3(eHUBO7\\8\"F67$7$$!3a\"e@.PoId#F6$\"3;srrrrrr6F6FZ7$7$$!33 \"e@.PoId#F6$\"3#><<<<<<<\"F67$$!3+2[tTpXvDF6$\"3IOBRp'o/>\"F67$7$$!35 /wRI1vzDF6$\"3aAAAAAAA7F6Feo7$F[p7$$!3O2$p#\\I<#e#F6$\"3w\\k5(Gr^C\"F6 7$7$$!31;?(RMb`e#F6$\"3;tssssss7F6Fap7$Fgp7$$!3sq#o3A^ve#F6$\"3i_3'[pP !*H\"F67$7$$!3Cccj'ph)*e#F6$\"3wBBBBBBB8F6F]q7$Fcq7$$!3#4U\"3n]i\"f#F6 $\"3c@\"\\#**))3_8F67$7$$!357V+7VD$f#F6$\"3Outttttt8F6Fiq7$F_r7$$!3Sx6 p#QLWf#F6$\"3.q-,Z\"\\VS\"F67$7$$!3AG#QHCBbf#F6$\"3)\\UUUUUUU\"F6Fer7$ F[s7$$!3/+(GFe>gf#F6$\"3Ws(QDdXeX\"F67$7$$!3i%3Xq&Qm'f#F6$\"3evuuuuuu9 F6Fas7$Fgs7$$!3'*=&)*)f5V'f#F6$\"3+g\\F'z2m]\"F67$7$$!3%[xJhiwmf#F6$\" 3>EDDDDDD:F6F]t7$7$$!3Iv<8Emn'f#F6$\"3UEDDDDDD:F67$$!3wNS8!\\=df#F6$\" 3m3sn!\\nmb\"F67$7$$!3_@t&>$oc&f#F6$\"3!oddddddd\"F6F^u7$Fdu7$$!3=(\\s A6NRf#F6$\"3#yz=+$z01;F67$7$$!3#*\\9`-UM$f#F6$\"3TFEEEEEE;F6Fju7$F`v7$ $!3=8[$f+O6f#F6$\"3g&zi!RN\"[l\"F67$7$$!3YK\"yU\\A+f#F6$\"3-ywwwwww;F6 Ffv7$7$F]w$\"3yxwwwwww;F67$$!3)p^))))Qxte#F6$\"3I6R\"RXpHq\"F67$7$$!3q '=vc.>ce#F6$\"3SGFFFFFFW=F67$7$$!3)4nG*)*[8mDF6$\"3W !)yyyyyy=F6F_z7$Fez7$$!3gSp1ni(Qc#F6$\"3EGcza9I!*=F67$7$$!3)y*R*=FKwb# F6$\"31JHHHHHH>F6F[[l7$Fa[l7$$!3[?=^o(fhb#F6$\"3\"*GPq$p$)f$>F67$7$$!3 i&oy\\Er\"[DF6$\"3W\")zzzzzz>F6Fg[l7$7$F^\\l$\"3o\")zzzzzz>F67$$!3OnF67$7$F4$\"3SybepLz#*>F6Ff\\l7$7$$!3?jkkkkkkCF6 $\"3OnG_N8dht!#=7$$!3%ySD;5e_Z#F6$\"37vwwwwwwwFe]l7$Ff]l7$$!3Wjg)>=&)z Z#F6$\"3gw,9gY8gxFe]l7$7$$!39x'*y1+W\"\\#F6$\"3A\"=======)Fe]lF\\^l7$F b^l7$$!37fXk.9\"y\\#F6$\"3#zFc00*4*Q)Fe]l7$7$$!39IGFd%zn]#F6$\"31&oooo ooo)Fe]lFh^l7$F^_l7$$!3=zhSy#)*f^#F6$\"3&*4p'G_>>>>>>*Fe]lFd_l7$7$F[`l$\"3%*)=>>>>>>*Fe]l7$$!3$)zf$*[/_KD F6$\"3bp'GPfJhh*Fe]l7$7$$!3e(R;\")zdY`#F6$\"3-&ppppppp*Fe]lFc`l7$Fi`l7 $F4$\"3dz+'\\bPO,\"F67$F\\]l7$$!3hvZ%*4)=x`#F6$\"3$pU4c>oa-#F67$7$$!3M \")3&)p>yODF6$\"30KIIIIII?F6Fcal7$7$$!3*3)3&)p>yODF6F\\bl7$$!3on>3ldiE DF6$\"3SA_2$4S!p?F67$7$$!3SzR!H/mS_#F6$\"3m#3333333#F6Fbbl7$7$$!3'*yR! 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Given the equation \+ " }{XPPEDIT 18 0 "x*cos(Pi*y) = (x+y)^2;" "6#/*&%\"xG\"\"\"-%$ cosG6#*&%#PiGF&%\"yGF&F&*$),&F%F&F,F&\"\"#F&" }{TEXT 276 1 " " }} {PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 48 " (a) \+ Plot a graph of the equation for -8 " }{TEXT 262 1 "<" }{TEXT 276 2 " " }{TEXT 263 1 "x" }{TEXT 276 2 " " }{TEXT 264 1 "<" }{TEXT 276 10 " 8 , -5 " }{TEXT 265 1 "<" }{TEXT 276 2 " " }{TEXT 266 1 "y " }{TEXT 276 2 " " }{TEXT 267 1 "<" }{TEXT 276 5 " 6 ." }}{PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 36 " (b) Verify t hat the point P = " }{TEXT 268 2 "( " }{XPPEDIT 18 0 "(23+sqrt(129))/ 12;" "6#*&,&\"#B\"\"\"-%%sqrtG6#\"$H\"F&F&\"#7!\"\"" }{TEXT 276 5 " , " }{TEXT 203 1 " " }{XPPEDIT 18 0 "-5/3;" "6#,$*&\"\"&\"\"\"\"\"$!\" \"F(" }{TEXT 203 2 " " }{TEXT 269 1 ")" }{TEXT 276 34 " is on the gr aph of the equation." }{MPLTEXT 1 0 1 " " }}{PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 13 " (c) Use " }{TEXT 270 5 "Mapl e" }{TEXT 276 10 " to find " }{XPPEDIT 18 0 "dy/dx;" "6#*&%#dyG\"\"\" %#dxG!\"\"" }{TEXT 276 3 " ." }{MPLTEXT 1 0 0 "" }}{PARA 0 "" 0 "" {TEXT 276 62 " (d) Find the slope of the tangent line to the curve at P." }}{PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 75 " (e) Plot the graph of the curve and the tangent on the same set of axes." }}{PARA 0 "" 0 "" {TEXT 276 0 "" }}{PARA 0 "" 0 "" {TEXT 276 24 "2.) Given the equation " }}{PARA 0 "" 0 "" {TEXT 276 16 " \+ " }{XPPEDIT 18 0 "y^4-4*y^2 = x^4-9*x^2;" "6#/,&*$)%\"yG\" \"%\"\"\"F)*&F(F)*$)F'\"\"#F)F)!\"\",&*$)%\"xGF(F)F)*&\"\"*F)*$)F2F-F) F)F." }{TEXT 276 23 ", P=(3,2) , -5 " }{TEXT 271 2 "< " }{TEXT 276 2 "x " }{TEXT 272 1 "<" }{TEXT 276 8 "5 , -5 " }{TEXT 273 1 "<" }{TEXT 276 3 " y " }{TEXT 274 1 "<" }{TEXT 276 1 " " }{TEXT 203 2 "5," }}{PARA 13 "" 0 "" {TEXT 278 0 "" }}{PARA 0 "" 0 "" {TEXT 276 39 " \+ do a), b), c) , d), e.) and also:" }}{PARA 0 "" 0 "" {TEXT 276 108 " (f) Solve the equation for y. There will be four solutions, eac h a function of x. Determine which part" }}{PARA 0 "" 0 "" {TEXT 276 283 " of the graph of the equation is the graph of each of th ese four equations. Plot all four solutions on the same \+ graph in different colors. (If you print out \+ on a non-color printer make a seperate graph for each of the four func tions.) " }}{PARA 0 "" 0 "" {TEXT 276 2 " " }}{PARA 13 "" 0 "" {TEXT 278 0 "" }}{PARA 0 "" 0 "" {TEXT 276 6 " " }}} {MARK "0 0 0" 0 }{VIEWOPTS 0 0 0 1 1 1803 1 1 1 1 }{PAGENUMBERS 0 1 2 33 1 1 }